Optimal. Leaf size=81 \[ -\frac {2}{3} a^{3/2} A \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )+\frac {2}{9} A \left (a+b x^3\right )^{3/2}+\frac {2}{3} a A \sqrt {a+b x^3}+\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b} \]
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Rubi [A] time = 0.06, antiderivative size = 81, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.227, Rules used = {446, 80, 50, 63, 208} \begin {gather*} -\frac {2}{3} a^{3/2} A \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )+\frac {2}{9} A \left (a+b x^3\right )^{3/2}+\frac {2}{3} a A \sqrt {a+b x^3}+\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b} \end {gather*}
Antiderivative was successfully verified.
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Rule 50
Rule 63
Rule 80
Rule 208
Rule 446
Rubi steps
\begin {align*} \int \frac {\left (a+b x^3\right )^{3/2} \left (A+B x^3\right )}{x} \, dx &=\frac {1}{3} \operatorname {Subst}\left (\int \frac {(a+b x)^{3/2} (A+B x)}{x} \, dx,x,x^3\right )\\ &=\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b}+\frac {1}{3} A \operatorname {Subst}\left (\int \frac {(a+b x)^{3/2}}{x} \, dx,x,x^3\right )\\ &=\frac {2}{9} A \left (a+b x^3\right )^{3/2}+\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b}+\frac {1}{3} (a A) \operatorname {Subst}\left (\int \frac {\sqrt {a+b x}}{x} \, dx,x,x^3\right )\\ &=\frac {2}{3} a A \sqrt {a+b x^3}+\frac {2}{9} A \left (a+b x^3\right )^{3/2}+\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b}+\frac {1}{3} \left (a^2 A\right ) \operatorname {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,x^3\right )\\ &=\frac {2}{3} a A \sqrt {a+b x^3}+\frac {2}{9} A \left (a+b x^3\right )^{3/2}+\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b}+\frac {\left (2 a^2 A\right ) \operatorname {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+b x^3}\right )}{3 b}\\ &=\frac {2}{3} a A \sqrt {a+b x^3}+\frac {2}{9} A \left (a+b x^3\right )^{3/2}+\frac {2 B \left (a+b x^3\right )^{5/2}}{15 b}-\frac {2}{3} a^{3/2} A \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )\\ \end {align*}
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Mathematica [A] time = 0.08, size = 80, normalized size = 0.99 \begin {gather*} \frac {2 \left (-15 a^{3/2} A b \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right )+5 A b \left (a+b x^3\right )^{3/2}+15 a A b \sqrt {a+b x^3}+3 B \left (a+b x^3\right )^{5/2}\right )}{45 b} \end {gather*}
Antiderivative was successfully verified.
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IntegrateAlgebraic [A] time = 0.07, size = 85, normalized size = 1.05 \begin {gather*} \frac {2 \sqrt {a+b x^3} \left (3 a^2 B+20 a A b+6 a b B x^3+5 A b^2 x^3+3 b^2 B x^6\right )}{45 b}-\frac {2}{3} a^{3/2} A \tanh ^{-1}\left (\frac {\sqrt {a+b x^3}}{\sqrt {a}}\right ) \end {gather*}
Antiderivative was successfully verified.
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fricas [A] time = 0.82, size = 172, normalized size = 2.12 \begin {gather*} \left [\frac {15 \, A a^{\frac {3}{2}} b \log \left (\frac {b x^{3} - 2 \, \sqrt {b x^{3} + a} \sqrt {a} + 2 \, a}{x^{3}}\right ) + 2 \, {\left (3 \, B b^{2} x^{6} + {\left (6 \, B a b + 5 \, A b^{2}\right )} x^{3} + 3 \, B a^{2} + 20 \, A a b\right )} \sqrt {b x^{3} + a}}{45 \, b}, \frac {2 \, {\left (15 \, A \sqrt {-a} a b \arctan \left (\frac {\sqrt {b x^{3} + a} \sqrt {-a}}{a}\right ) + {\left (3 \, B b^{2} x^{6} + {\left (6 \, B a b + 5 \, A b^{2}\right )} x^{3} + 3 \, B a^{2} + 20 \, A a b\right )} \sqrt {b x^{3} + a}\right )}}{45 \, b}\right ] \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.16, size = 80, normalized size = 0.99 \begin {gather*} \frac {2 \, A a^{2} \arctan \left (\frac {\sqrt {b x^{3} + a}}{\sqrt {-a}}\right )}{3 \, \sqrt {-a}} + \frac {2 \, {\left (3 \, {\left (b x^{3} + a\right )}^{\frac {5}{2}} B b^{4} + 5 \, {\left (b x^{3} + a\right )}^{\frac {3}{2}} A b^{5} + 15 \, \sqrt {b x^{3} + a} A a b^{5}\right )}}{45 \, b^{5}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.05, size = 66, normalized size = 0.81 \begin {gather*} \left (\frac {2 \sqrt {b \,x^{3}+a}\, b \,x^{3}}{9}-\frac {2 a^{\frac {3}{2}} \arctanh \left (\frac {\sqrt {b \,x^{3}+a}}{\sqrt {a}}\right )}{3}+\frac {8 \sqrt {b \,x^{3}+a}\, a}{9}\right ) A +\frac {2 \left (b \,x^{3}+a \right )^{\frac {5}{2}} B}{15 b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 1.26, size = 80, normalized size = 0.99 \begin {gather*} \frac {2 \, {\left (b x^{3} + a\right )}^{\frac {5}{2}} B}{15 \, b} + \frac {1}{9} \, {\left (3 \, a^{\frac {3}{2}} \log \left (\frac {\sqrt {b x^{3} + a} - \sqrt {a}}{\sqrt {b x^{3} + a} + \sqrt {a}}\right ) + 2 \, {\left (b x^{3} + a\right )}^{\frac {3}{2}} + 6 \, \sqrt {b x^{3} + a} a\right )} A \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.79, size = 131, normalized size = 1.62 \begin {gather*} \frac {A\,a^{3/2}\,\ln \left (\frac {{\left (\sqrt {b\,x^3+a}-\sqrt {a}\right )}^3\,\left (\sqrt {b\,x^3+a}+\sqrt {a}\right )}{x^6}\right )}{3}+\frac {\sqrt {b\,x^3+a}\,\left (2\,B\,a^2+4\,A\,a\,b-\frac {2\,a\,\left (2\,A\,b^2+\frac {12\,B\,a\,b}{5}\right )}{3\,b}\right )}{3\,b}+\frac {2\,B\,b\,x^6\,\sqrt {b\,x^3+a}}{15}+\frac {x^3\,\left (2\,A\,b^2+\frac {12\,B\,a\,b}{5}\right )\,\sqrt {b\,x^3+a}}{9\,b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 66.50, size = 82, normalized size = 1.01 \begin {gather*} \frac {2 A a^{2} \operatorname {atan}{\left (\frac {\sqrt {a + b x^{3}}}{\sqrt {- a}} \right )}}{3 \sqrt {- a}} + \frac {2 A a \sqrt {a + b x^{3}}}{3} + \frac {2 A \left (a + b x^{3}\right )^{\frac {3}{2}}}{9} + \frac {2 B \left (a + b x^{3}\right )^{\frac {5}{2}}}{15 b} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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